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Subject: Re: Formula for Available Power?
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Date: 08/23/03 at 6:06 PM
Posted by: Russ Kincaid
E-mail: russlk-nospam[AT55]yahoo.com (replace [AT55] with @ to reply)
In Reply to: Re: Formula for Available Power? posted by Randy Gross on 08/22/03 at 3:50 PM:
If this transformer is operating on 120 VAC, 60 Hz, I am surprised it does not blow a fuse with only 50 turns on the primary. At any rate, the turns ratio is: 50/7=7.14. If the primary current (due to secondary load) is 6 amps, the secondary current will be: 7.14*6=42.86 amps.
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